遇到一个关于php7 json_decode null问题!

具体问题描述:

1、确认文件无BOM头

2、尝试了如下多种方式去除非法字符串,但是仍然输出NULL

        $some_string = htmlspecialchars_decode($some_string);
        $some_string = preg_replace("/\t/", " ", $some_string);
        $some_string = preg_replace("/\n/", ' ', $some_string);
        $some_string = str_replace("\n", ' ', $some_string);
        $some_string = str_replace ('\n','', $some_string);

3、json_last_error()输出4,Syntax error, malformed JSON

4、直接输出字符串,浏览器能够正常解析josn,如下截图

6b3060b88d738528229eef4e0ba2529.png

解决办法:

因为你的字符串不是标准的JSON字符串, 标准的JSON字符串每个string类型都要用"引起了

测试代码

<?php 
$jsonStr1 = '{status: {RetCode:0, msg: "success"}, data: {}}';
var_dump(json_decode($jsonStr1, true));
var_dump(json_last_error());
echo "--------分割线--------".PHP_EOL;
$jsonStr2 = '{"status": {"RetCode":0, "msg": "success"}, "data": {}}';
var_dump(json_decode($jsonStr2, true));

结果

NULL
int(4)
--------分割线--------
array(2) {
  ["status"]=>
  array(2) {
    ["RetCode"]=>
    int(0)
    ["msg"]=>
    string(7) "success"
  }
  ["data"]=>
  array(0) {
  }
}

============== 更新 ==============

经过调试,发现是 BOM 引起的,下面是解决方案

$dataString = $merchant_arr['data'];
$A = substr($dataString, 0, 1);
$B = substr($dataString, 1, 1);
$C = substr($dataString, 2, 1);
if ((ord($A) == 239) && (ord($B) == 187) && (ord($C) == 191)) {
    $dataString = substr($dataString, 3);
}
$dataArray = json_decode($dataString, true);


遇到一个关于php7 json_decode null问题!